.18x^2+15x-12=0

Solution for .18x^2+15x-12=0 equation:

.18x^2+15x-12=0

a = .18; b = 15; c = -12;
Δ = b2-4ac
Δ = 152-4·.18·(-12)
Δ = 233.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{233.64}}{2*.18}=\frac{-15-\sqrt{233.64}}{0.36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{233.64}}{2*.18}=\frac{-15+\sqrt{233.64}}{0.36}
$